Identifying, Testing and Troubleshooting Semiconductor Components.
6 resistors were given to me with the aim to determine there values two ways:
Resistor 1:
When in parallel Rt (total resistance) is less than any one branches resistance.
Rt = R1xR2/R1+R2 (Formula is for two resistors only).
or for three resistors:
Rt=R1xR2/R1+R2=R3
Rt=R2xR3/R2+R3
- Using the colour code chart (as shown)
- Using an ohmmeter across the resistors
- Also the max and min tolerances were asked for
Resistor 1:
- Measured value = 986Ω
- Calculated value = Brown (1), Black (0), Red (2), Gold (5%) =1KΩ
- Tolerance Level = (950-1050)Ω
- Measured Value = 46700Ω
- Calculated Value = Yellow (4), Violet (7), Orange (3), Gold (5%) = 47000Ω
- Tolerance Level = (44650-49350)Ω
- Measured Value = 99.7Ω
- Calculated Value = Brown (1), Black (0), Brown (1), Gold (5%) = 100Ω
- Tolerance Level = (95-105)Ω
- Measured Value = 99.3Ω
- Calculated Value = Brown (1), Black (0), Brown (1), Gold (5%) = 100Ω
- Tolerance Level = (95-105)Ω
- Measured Value = 2170Ω
- Calculated Value = Red (2), Red (2), Red (2), Gold (5%) = 2200Ω
- Tolerance Level = (2090-2310)Ω
- Measured Value = 465Ω
- Calculated Value = Yellow (4), Violet (7), Brown (1), Gold (5%) = 470Ω
- Tolerance Level = (446.5-493.5)Ω
- Resistor 1 = 2170Ω
- Resistor 2 = 465Ω
- Calculated resistance of resistors 1 and 2 in series = 2670Ω (Add them together)
- Measured resistance of resistors 1 and 2 in series = 2640Ω
- Calculated resistance of resistors 1 and 2 in parallel = 940Ω = (2200x470/2200+470)
- Measured resistance of resistors 1 and 2 in parallel = 383Ω
When in parallel Rt (total resistance) is less than any one branches resistance.
Rt = R1xR2/R1+R2 (Formula is for two resistors only).
or for three resistors:
Rt=R1xR2/R1+R2=R3
Rt=R2xR3/R2+R3
Experiment 1
ReplyDeleteWrite 1000 ohms as 1 Kilohm.
Resistor #2 does not exist!
What is the formula for more than two resistors in parallel?
Experiment 2
You did not use an 'ohmmeter' on diode test.
The LED readings are incorrect.
Both leads of a diode are of the same length.
Experiment 2
ReplyDelete31.6 mA is not correct.
You are not using your meter correctly to measure the LED current.
Experiment 3
ReplyDeleteDo not use phrases such as 'could potentially', be specific; it either is or is not.
How big is 'big'; your statement is not correct about the difference in voltage.
Experiment 4
ReplyDeleteWrite 0.010 A as 10 mA.
When are you going to update your blog?
ReplyDeleteStill no updates!
ReplyDeleteOnly one week left.